This is a picture of an isosceles triangle that has two EQUAL angles on the bottom. What is the value of EACH angle?

35 Both angles (x) have to be the same. All three have to add up to 180.

What is the area formula for a square?

Area = base x height OR Area = length x width

What is the Perimeter formula for a square?

Add up all the sides. Length + Length + Length + Length OR 4 x (L)

What is the area formula for a rectangle?

Area = base x height OR Area = length x width

What is the Perimeter formula for a rectangle?

Add up all the sides. Length + Length + Width + Width OR 2(L) + 2(W)

What is the area formula for a triangle?

1/2 Base x Height OR 1/2 Height x Base OR Base x Height then divide by 2

What is the Circumference formula for a circle? Remember: Circumference is like the perimeter of a circle

$$Circumference\ =\ \pi\ \cdot\ D$$ OR $$Circumference\ =\ \pi\ \cdot\ 2r$$

What is the formula to find the VOLUME of a rectangular prism (box)?

First find the area of the bottom base square... Then multiply by the height. Volume = B (h) OR Volume = length x width x height

What is the formula for finding the VOLUME of a triangular prism?

First find the area of the base triangle... Then multiply by the height. Volume = B (h)

What is the formula for the VOLUME of a cylinder?

First find the area of the base circle. Then multiply by the height. Volume = B (h)

Describe how you would find the area of the pink figure.

1. Find the area of the small rectangle. 2. Then add it to the area of the large rectangle.

Describe how you would find the area of the shaded blue shape.

1. Find the area of the large rectangle. 2. Then subtract the area of the small triangle from it.

How could you easily find the Diameter of a circle if they give you the Circumference?

Since the Circumference formula is: $$C\ =\ \pi\ \cdot\ D$$ All you would need to do to find the diameter is DIVIDE BY PI.

If you knew the Diameter of a circle, how could you easily find the radius?

Since the Diameter is all the way across, and the radius is half-way across... Just DIVIDE THE DIAMETER BY 2.

If you knew the radius of a circle, how could you easily find the diameter?

Since the Diameter is all the way across, and the radius is half-way across... Just MULTIPLY THE RADIUS BY 2.

How do you find the SURFACE AREA of a box?

Area of TOP + Area of BOTTOM + Area of LEFT + Area of RIGHT + Area of FRONT + Area of BACK. In other words, find the area of all the flat sides and add them all together.

Solve for x x + 5 = 11

x + 5 = 11 -5 from both sides x = 6

Solve for x: x - 2 = 7

x - 2 = 7 +2 to both sides x = 9

3x = 21 Divide both sides by 3 x = 7

Solve for x: $$\frac{x}{4}\ \ =\ \ 12$$

$$\frac{x}{4}\ \ =\ \ 12$$ Multiply both sides by 4 x = 48

What is the only difference in solving INEQUALITIES ( > < ) compared with solving equations?

The ONLY difference is: If you multiply or divide both sides by a negative number, the inequality sign gets flipped.

Solve for x: x + 7 < 11

x + 7 < 11 subtract 7 from both sides x < 4 Notice that the sign stays the same.

Solve for x: x - 8 > 12

x - 8 > 12 Add 8 to both sides x > 20 Notice that the sign stays the same

2x < 12 Divide both sides by 2 x < 6 Notice that the sign stays the same.

7 Flash A (Total) Flashcards

Student preview

103 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What kind of angle is SMALLER than 90 degrees?

Back

Acute Angle

Tags

CCSS.4.G.A.1

2.

FLASHCARD QUESTION

Front

What kind of angle is EQUAL to 90 degrees?

Back

Right Angle

Tags

CCSS.4.G.A.1

3.

FLASHCARD QUESTION

Front

What kind of angle is BIGGER than 90 degrees?

Back

Obtuse angle

Tags

CCSS.4.G.A.1

4.

FLASHCARD QUESTION

Front

What kind of angle is EQUAL to 180 degrees?

Back

Straight angle

Tags

CCSS.4.G.A.1

5.

FLASHCARD QUESTION

Front

What kind of angle is this?

Back

Right angle

Tags

CCSS.4.G.A.1

6.

FLASHCARD QUESTION

Front

What kind of angle is this?

Back

Acute angle

Tags

CCSS.4.G.A.1

7.

FLASHCARD QUESTION

Front

What kind of angle is this?

Back

Straight angle

Tags

CCSS.4.G.A.1

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