
Flashcard 5-2 Review Problems 1 (2023)
Flashcard
•
Mathematics
•
9th Grade
•
Practice Problem
•
Hard
+6
Standards-aligned
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the equivalent of 89°11'15" in decimal degrees?
Back
89.2 degrees
2.
FLASHCARD QUESTION
Front
How do you calculate the angle of elevation when viewing an object from a height?
Back
Use the tangent function: tan(x) = opposite/adjacent. In this case, opposite is the height and adjacent is the horizontal distance.
Tags
CCSS.HSG.SRT.C.8
3.
FLASHCARD QUESTION
Front
What is the value of tan(-π)?
Back
0
Tags
CCSS.HSF.TF.A.2
4.
FLASHCARD QUESTION
Front
How do you find the height of an object using the angle of elevation?
Back
Use the formula: height = distance * tan(angle).
Tags
CCSS.HSG.SRT.C.8
5.
FLASHCARD QUESTION
Front
What is the angle of elevation?
Back
The angle formed between the horizontal line and the line of sight to an object above the horizontal.
Tags
CCSS.8.G.A.5
6.
FLASHCARD QUESTION
Front
What is the formula for converting degrees and minutes to decimal degrees?
Back
Decimal degrees = degrees + (minutes/60) + (seconds/3600).
Tags
CCSS.HSF.TF.A.1
7.
FLASHCARD QUESTION
Front
If a tourist is 45 feet above the ground and sees a deer 130 feet away, how do you find the angle of elevation?
Back
Use the formula: angle = arctan(opposite/adjacent) = arctan(45/130).
Tags
CCSS.HSG.SRT.C.8
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