
Pythagorean Theorem and Special Right Triangles
Flashcard
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Hard
+2
Standards-aligned
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1.
FLASHCARD QUESTION
Front
What is the Pythagorean Theorem?
Back
The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). It can be expressed as: c² = a² + b².
Tags
CCSS.8.G.B.8
2.
FLASHCARD QUESTION
Front
What are the special right triangles?
Back
The special right triangles are the 45-45-90 triangle and the 30-60-90 triangle. In a 45-45-90 triangle, the legs are equal, and the hypotenuse is √2 times the length of a leg. In a 30-60-90 triangle, the lengths of the sides are in the ratio 1:√3:2.
Tags
CCSS.8.G.B.8
3.
FLASHCARD QUESTION
Front
How do you find the length of the hypotenuse in a right triangle?
Back
To find the length of the hypotenuse (c) in a right triangle, use the Pythagorean Theorem: c = √(a² + b²), where a and b are the lengths of the other two sides.
Tags
CCSS.8.G.B.7
4.
FLASHCARD QUESTION
Front
What is the length of the legs in a 45-45-90 triangle if the hypotenuse is 10?
Back
In a 45-45-90 triangle, the legs are equal and can be found using the formula: leg = hypotenuse / √2. Therefore, if the hypotenuse is 10, each leg is 10/√2 = 5√2.
Tags
CCSS.8.G.B.8
5.
FLASHCARD QUESTION
Front
What is the ratio of the sides in a 30-60-90 triangle?
Back
The ratio of the sides in a 30-60-90 triangle is 1:√3:2, where the side opposite the 30° angle is 1, the side opposite the 60° angle is √3, and the hypotenuse is 2.
Tags
CCSS.HSG.CO.C.10
6.
FLASHCARD QUESTION
Front
If one leg of a 30-60-90 triangle is 5, what is the length of the hypotenuse?
Back
In a 30-60-90 triangle, the hypotenuse is twice the length of the shorter leg. Therefore, if one leg is 5, the hypotenuse is 5 * 2 = 10.
Tags
CCSS.HSG.CO.C.10
7.
FLASHCARD QUESTION
Front
What is the value of x in a right triangle with legs of length 3 and 4?
Back
Using the Pythagorean Theorem: c² = 3² + 4² = 9 + 16 = 25. Therefore, x (the hypotenuse) = √25 = 5.
Tags
CCSS.8.G.B.7
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