Inverse Trig Ratios

Front

Which equation is true?
Options: sin (x) = 14/29, cos (x) = 14/29, tan (x) = 14/29, tan (x) = 29/14

Back

tan (x) = 14/29

Tags

CCSS.HSG.SRT.C.6

Front

Which equation is true?
Options: sin (x) = 11/27, sin (x) = 27/11 , cos (x) = 11/27 , tan (x) = 11/27

Back

sin (x) = 11/27

Tags

CCSS.HSG.SRT.C.6

Front

Which equation is true? sin (x) = 6/8, cos (x) = 8/6, cos (x) = 6/8, tan (x) = 6/8

Back

cos (x) = 6/8

Tags

CCSS.HSG.SRT.C.6

Front

Which equation would you use to solve for the unknown angle? Options: x = sin^–1(4/5), x = cos^–1(4/5), x = cos^–1(5/4), x = tan^–1(4/5)

Back

x = cos^–1(4/5)

Tags

CCSS.HSG.SRT.C.8

Front

Which equation would you use to solve for the unknown angle? Options: x = tan^–1(24/7), x = tan^–1(7/24), x = tan^–1(25/7), x = tan^–1(7/25)

Back

x = tan^–1(24/7)

Tags

CCSS.HSG.SRT.C.8

Front

Which equation could be used to solve for the unknown angle? Options: x =sin^–1(25/24), x = sin^–1(24/25), x = sin^–1(25/7), x = sin^–1(7/25)

Back

x = sin^–1(24/25)

Tags

CCSS.HSG.SRT.C.8

Front

Which equation would you use to solve for the unknown angle? Options: x =tan^–1(51/85), x = tan^–1(85/51), x = tan^–1(51/68), x = tan^–1(68/51)

Back

x = tan^–1(51/68)

Tags

CCSS.HSG.SRT.C.8

Front

Which equation would you use to solve for the unknown angle? Options: x =cos^–1(68/85), x = cos^–1(85/68), x = cos^–1(51/85), x = cos^–1(85/51)

Back

x =cos^–1(68/85)

Tags

CCSS.HSG.SRT.C.8

Front

Which equation would you use to solve for the unknown angle? Options: x = sin^–1(56/70), x = sin^–1(70/56), x = sin^–1(70/42), x = sin^–1(42/70)

Back

x = sin^–1(42/70)

Tags

CCSS.HSG.SRT.C.8

Front

Solve for x.

Back

x = 30º

Tags

CCSS.HSG.SRT.C.8