Kebarangkalian
Flashcard
•
Mathematics
•
10th Grade
•
Practice Problem
•
Easy
Fikriyah Hidayah
Used 2+ times
FREE Resource
Student preview

10 questions
Show all answers
1.
FLASHCARD QUESTION
Front
Dua buah buku dipilih secara rawak daripada sebuah rak buku yang mengandungi dua buah buku sejarah (S), sebuah buku geografi (G) dan sebuah buku Matematik (M). Tulis ruang sampel bagi peristiwa bergabung berikut.
Back
S = {(S1, S2), (S1, G), (S1, M), (S2, S1), (S2, G), (S2, M), (G, S1), (G, S2), (G, M), (M, S1), (M, S2), (M, G)}
2.
FLASHCARD QUESTION
Front
Mendapat dua keping kad yang berhuruf sama apabila dua keping kad dipilih secara rawak daripada kad berlabel dengan huruf "B A I K" satu demi satu dengan pemulangan.
Tentukan jenis peristiwa di atas sama ada Peristiwa Bersandar atau Peristiwa Tak Bersandar.
Back
Peristiwa Tak Bersandar
3.
FLASHCARD QUESTION
Front
Tulis ruang sampel bagi penyataan di bawah.
Jantina anak bagi keluarga yang mempunyai dua orang anak.
Back
S = {(L , L), (L , P), (P , L), (P , P)}
4.
FLASHCARD QUESTION
Front
Mendapat 2 biji guli yang sama warna apabila 2 biji guli dikeluarkan satu demi satu tanpa pemulangan dari sebuah kotak yang mengandungi 4 biji guli merah dan 3 biji guli biru.
Tentukan sama ada peristiwa berikut ialah peristiwa bersandar atau peristiwa tak bersandar.
Back
Peristiwa Bersandar
5.
FLASHCARD QUESTION
Front
Sebiji dadu adil dan sekeping duit syiling adil dilambung secara serentak.
Tulis ruang sampel bagi penyataan di atas.
Back
S = {(1 , A), (1 , G), (2 , A), (2 , G), (3 , A), (3 , G), (4 , A), (4 , G), (5 , A), (5 , G), (6 , A), (6 , G)}
6.
FLASHCARD QUESTION
Front
Rahmad dan Aziz masing-masing mendapat A dalam ujian Biologi di sekolah.
Tentukan sama ada peristiwa di atas ialah peristiwa bersandar atau peristiwa tak bersandar.
Back
Peristiwa Tak Bersandar
7.
FLASHCARD QUESTION
Front
Dua keping surat dipilih secara rawak daripada sebuah kotak yang mengandungi tiga keping surat berwarna putih, hijau dan biru tanpa pemulangan.
Tulis ruang sampel bagi peristiwa bergabung berikut.
Back
S = {(P , H), (P , B), (H , P), (H , B). (B , P), (B , H)}
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