2.2-2.3 - Solving Absolute Value Equations and Inequalities

Front

Back

Front

Solve for a: |2a - 10| = 6

Back

a = 8, a = 2

Front

Back

no solution

Front

Back

Front

∣ 2x + 9 ∣ = 15

Back

x = 3
x = -12

Front

Back

Front

Solve: |x + 3| > 8

Back

x > 5 or x < -11

Front

| 2w - 1 | < 11

Back

-5 < w < 6

Front

| x + 3 | ≤ 2

Back

-5 ≤ x ≤ -1

Front

3 | 2t - 3 | - 5 > 16

Back

t < -2 or t > 5