
Circle Segment Relationships Quiz

Interactive Video
•
Mathematics
•
9th - 10th Grade
•
Hard
Jennifer Brown
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the relationship between the segments of two intersecting chords in a circle?
The difference between the segments of one chord equals the difference of the segments of the other.
The product of the segments of one chord equals the product of the segments of the other.
The ratio of the segments of one chord equals the ratio of the segments of the other.
The sum of the segments of one chord equals the sum of the segments of the other.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the example where 2x equals 18, what is the value of x?
9
12
8
6
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When solving a quadratic equation from intersecting chords, why might a negative solution be rejected?
Negative solutions are always incorrect.
Negative solutions do not make sense for segment lengths.
Negative solutions are not allowed in geometry.
Negative solutions are only used in algebra.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do we prove the segment product relationship using triangles?
By using the Pythagorean theorem.
By showing the triangles are congruent.
By using the law of sines.
By using angle-angle similarity to show triangles are similar.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens to a chord that is perpendicular to a diameter in a circle?
It is divided into three equal parts.
It is parallel to the diameter.
It becomes a tangent to the circle.
It is bisected by the diameter.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If a chord is 24 cm long and perpendicular to a diameter, what is the length of each segment?
10 cm
8 cm
6 cm
12 cm
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How can the symmetry of a circle help prove that a perpendicular chord is bisected by a diameter?
By showing that the circle is a perfect square.
By proving that the circle is a regular polygon.
By illustrating that the circle is a tangent to the diameter.
By demonstrating that the circle is a mirror image across the diameter.
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