XeF4 Molecular Structure and Properties

Dr. B explains how to draw the Lewis structure for XeF4, starting with the placement of atoms and bonds, and then filling the octets. He calculates the formal charges and identifies an imbalance, suggesting a double bond to optimize the structure. The final structure has zero formal charges on all atoms, making it the best representation for XeF4.

How many valence electrons are present in the XeF4 molecule?

• 32

• 42

• 52

• 62

Which atom is placed at the center of the XeF4 Lewis structure?

• Oxygen

• Fluorine

• Carbon

• Xenon

How many electrons are used in forming bonds between the atoms in XeF4?

• 6

• 8

• 12

• 10

What is the formal charge on the oxygen atom before adjusting the structure?

• +1

• 0

• -1

• -2

What adjustment is made to achieve zero formal charges on all atoms in XeF4?

• Removing electrons from xenon

• Adding more electrons to fluorine

• Adding an extra oxygen atom

• Forming a double bond with xenon

What is the final formal charge on all atoms in the optimized XeF4 structure?

• +1

• 0

• -1

• +2