Valence Electrons in SeCl4

Valence Electrons in SeCl4

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains the process of drawing the Lewis structure for SeCl4. It begins by identifying the total number of valence electrons and placing selenium at the center due to its lower electronegativity. Chlorine atoms are arranged around selenium, and electrons are distributed to form bonds and satisfy the octet rule. The tutorial highlights the use of all 34 valence electrons and explains the concept of an expanded octet for selenium, which allows it to have more than eight electrons. The video concludes with a complete Lewis structure for SeCl4.

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6 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are there in total for SeCl4?

36

34

32

30

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which atom is placed at the center of the SeCl4 Lewis structure?

Oxygen

Hydrogen

Chlorine

Selenium

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are used to form bonds between Se and Cl atoms initially?

12

8

10

6

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons used to complete the octets for all chlorine atoms?

32

24

30

28

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it acceptable for selenium to have more than 8 valence electrons in SeCl4?

Selenium is in period 3 and can have an expanded octet.

Selenium is highly electronegative.

Selenium is in period 2 and can have an expanded octet.

Selenium is a noble gas.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final number of valence electrons around the selenium atom in SeCl4?

14

12

10

8