Balancing Chemical Equations and Ions

This video tutorial demonstrates how to balance a chemical equation involving barium nitrate and sodium phosphate. It explains the process of counting atoms and polyatomic ions, and provides a step-by-step guide to balancing the equation by adjusting coefficients. The tutorial emphasizes the importance of treating polyatomic ions as single units to simplify the balancing process.

What is the main objective of the video tutorial?

• To discuss the uses of sodium phosphate

• To balance the chemical equation of barium nitrate and sodium phosphate

• To explain the properties of barium nitrate

• To demonstrate a chemical reaction experiment

What is a polyatomic ion?

• An ion that changes its structure during reactions

• An ion composed of multiple atoms that acts as a single unit

• An ion that does not participate in reactions

• An ion with a single atom

How many nitrate ions are present on the reactant side initially?

• Four

• Three

• Two

• One

What is the first step in balancing the equation?

• Balancing the sodium ions

• Balancing the barium ions

• Balancing the entire equation at once

• Balancing the phosphate ions

How many barium ions are needed on the product side to balance the equation?

• One

• Four

• Two

• Three

What adjustment is made to balance the nitrate ions?

• Reducing the number of phosphate ions

• Placing a coefficient of six in front of sodium nitrate

• Increasing the number of barium ions

• Adding more sodium ions

How many sodium ions are present on the reactant side after balancing?

• Nine

• Six

• Four

• Three

What coefficient is placed in front of sodium phosphate to balance the equation?

• One

• Four

• Two

• Three

What is the final step in balancing the equation?

• Balancing the barium ions

• Balancing the sodium ions

• Checking the entire equation for balance

• Balancing the phosphate ions

What is the balanced chemical equation for the reaction?

• Ba(NO3)2 + Na3PO4 → Ba3(PO4)2 + NaNO3

• 3Ba(NO3)2 + 2Na3PO4 → Ba3(PO4)2 + 6NaNO3

• 3Ba(NO3)2 + Na3PO4 → Ba3(PO4)2 + 6NaNO3

• Ba(NO3)2 + Na3PO4 → 3Ba3(PO4)2 + 6NaNO3