Valence Electrons in ClBr3

The video tutorial explains how to write the Lewis structure for chlorine tri-bromide (ClBr3). It begins by counting the valence electrons, noting that both chlorine and bromine are in group 17, contributing a total of 28 valence electrons. Chlorine is placed at the center with three bromines around it. Electron pairs are placed between atoms to form bonds, and octets are completed for the outer atoms. After using 24 electrons, the remaining are added to chlorine, which can have an expanded octet, resulting in the final Lewis structure.

How many total valence electrons are present in ClBr3?

• 14

• 28

• 21

• 35

Which atom is placed at the center of the ClBr3 Lewis structure?

• Bromine

• Chlorine

• Hydrogen

• Oxygen

How many valence electrons are used after completing the octets for the bromine atoms?

• 24

• 28

• 18

• 30

What is the total number of valence electrons left after completing the octets for bromine?

• 2

• 6

• 4

• 0

Why can chlorine have more than eight electrons in its valence shell in ClBr3?

• It forms ionic bonds.

• It is a noble gas.

• It is in period 3 and can have an expanded octet.

• It is a metal.

How many valence electrons are finally used in the ClBr3 Lewis structure?

• 28

• 24

• 30

• 26

What is the final configuration of the chlorine atom in the ClBr3 Lewis structure?

• It has an expanded octet.

• It has a complete octet.

• It forms a double bond with bromine.

• It has a deficient octet.