The video tutorial explains the concept of oxidation numbers, focusing on iodine (I2) and hydroiodic acid (HI). It highlights that I2 has an oxidation number of zero due to equal electronegativity between the two iodine atoms. In contrast, HI has a non-zero oxidation number because of the difference in electronegativity between hydrogen and iodine. The video also outlines rules for determining oxidation numbers, emphasizing that hydrogen typically has a +1 oxidation state when bonded to nonmetals, and iodine, being in group 17, usually has a -1 oxidation state.

What is the oxidation number of iodine in I2?

• +1

• +2

• 0

• -1

Why do molecules like I2 have an oxidation number of zero?

• Due to unequal sharing of electrons

• Because they are metals

• Due to equal sharing of electrons

• Because they are ionic compounds

In hydroiodic acid (HI), what is the oxidation number of hydrogen?

• -1

• 0

• +1

• +2

What causes the oxidation number of iodine to change in HI?

• Equal sharing of electrons

• Presence of a noble gas

• Difference in electronegativity

• Presence of a metal

What is the typical oxidation number for iodine in group 17?

• -1

• +2

• 0

• +1

When hydrogen is bonded to a nonmetal, what is its oxidation number?

• +2

• +1

• 0

• -1