Net Ionic Equations and Spectator Ions

Net Ionic Equations and Spectator Ions

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to write a balanced net ionic equation for the reaction between sodium hydroxide and aluminum nitrate. It begins by balancing the molecular equation, then determines the states of each substance involved. The tutorial proceeds to write the complete ionic equation by splitting strong electrolytes into ions. Spectator ions are identified and removed to derive the net ionic equation. The video concludes by ensuring charge and mass balance in the final equation.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in balancing net ionic equations?

Determine the solubility of compounds

Identify spectator ions

Write the net ionic equation

Balance the molecular equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is sodium hydroxide considered aqueous?

It is a weak base

It is insoluble in water

It forms a precipitate

It is a strong base and dissociates in water

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following compounds is generally insoluble?

Sodium nitrate

Potassium hydroxide

Aluminum hydroxide

Sodium hydroxide

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of the aluminum ion in the complete ionic equation?

3+

4+

2+

1+

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What do we call ions that do not participate in the reaction?

Reactive ions

Spectator ions

Active ions

Neutral ions

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are removed to form the net ionic equation?

Only negative ions

Spectator ions

Only positive ions

All ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the net ionic equation for the reaction between sodium hydroxide and aluminum nitrate?

3Na+ + 3OH- + Al3+ → Al(OH)3

NaOH + Al(NO3)3 → NaNO3 + Al(OH)3

3Na+ + 3NO3- + Al3+ → Al(OH)3

3OH- + Al3+ → Al(OH)3

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