

Balancing Chemical Equations with Odd Atoms
Interactive Video
•
Chemistry
•
9th - 10th Grade
•
Practice Problem
•
Hard
Emma Peterson
FREE Resource
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7 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the initial number of arsenic atoms on the reactant side of the equation?
Four
Two
Three
One
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it helpful to multiply by two when dealing with an odd number of atoms?
To make the equation more complex
To increase the number of atoms
To simplify the calculation
To convert the odd number to an even number
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of multiplying the number of arsenic atoms by two?
Two arsenic atoms
Eight arsenic atoms
Four arsenic atoms
Six arsenic atoms
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many oxygen atoms are there on the product side after balancing?
Five
Eight
Ten
Twelve
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What coefficient is placed in front of O2 to balance the oxygen atoms?
6
4
3
5
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final number of arsenic atoms on the reactant side after balancing?
Three
Four
Two
One
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the key takeaway when dealing with odd numbers in balancing equations?
Ignore the odd numbers
Multiply by two to make it even
Subtract atoms to balance
Always add more atoms
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