Chemical Reactions and Ionic Equations

Chemical Reactions and Ionic Equations

Assessment

Interactive Video

Chemistry

10th - 11th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial explains how to write the balanced net ionic equation for the decomposition of copper(II) hydroxide. It begins with balancing the molecular equation, followed by determining the states of the compounds using solubility rules. The tutorial then discusses the complete and net ionic equations, emphasizing that solids, liquids, and gases are not split into ions. The video concludes by summarizing that the decomposition of copper(II) hydroxide into copper(II) oxide and water does not result in a net ionic equation due to the lack of ion formation.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a balanced net ionic equation?

Balance the molecular equation

Write the complete ionic equation

Determine the solubility of compounds

Identify the spectator ions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to solubility rules, what is the general solubility of hydroxides?

Soluble

Insoluble

Soluble only in acids

Soluble only in bases

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What state symbol is used for insoluble compounds in a chemical equation?

(s)

(g)

(aq)

(l)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of solubility rules in writing net ionic equations?

To determine the color of compounds

To balance the equation

To determine the states of compounds

To identify spectator ions

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is not split into ions in a net ionic equation?

Aqueous solutions

Solids

Strong acids

Strong bases

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a strong electrolyte?

Water

Copper(II) hydroxide

Sodium chloride

Copper(II) oxide

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the complete ionic equation for copper(II) hydroxide decomposing?

Cu(OH)2 (s) → CuO (s) + H2O (l)

Cu2+ + 2OH- → CuO + H2O

Cu(OH)2 (aq) → Cu2+ + 2OH-

CuO + H2O → Cu(OH)2

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