Ionic Charges and Carbonate Compounds

The video tutorial explains how to write the formula for tin(IV) carbonate. It begins by identifying tin as a transition metal with a 4+ charge and the carbonate ion as a polyatomic ion with a 2- charge. The tutorial then demonstrates how to balance these charges to achieve a net charge of zero, resulting in the formula Sn(CO3)2. The process involves using parentheses to indicate two carbonate ions are associated with one tin atom.

What is the element symbol for tin as found on the periodic table?

• Ti

• Sn

• Tn

• Si

What does the Roman numeral IV indicate about tin in this context?

• It is the atomic number

• It is the number of electrons

• It indicates an ionic charge of 4+

• It is a group number

Which of the following is a polyatomic ion?

• O2

• CO3

• Na+

• Cl-

What is the ionic charge of the carbonate ion?

• 2-

• 2+

• 1-

• 3-

How many carbonate ions are needed to balance the charge of one tin ion in tin(IV) carbonate?

• Four

• Three

• One

• Two

What is the correct formula for tin(IV) carbonate?

• Sn(CO3)2

• Sn2(CO3)3

• SnCO3

• Sn(CO3)4