Oxidation States in CF4

Oxidation States in CF4

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to determine the oxidation numbers for elements in carbon tetrafluoride (CF4). It begins by noting that CF4 is a neutral compound, meaning the sum of oxidation numbers must equal zero. Fluorine, being more electronegative, always has an oxidation number of -1. With four fluorine atoms, the total is -4. To balance this, carbon must have an oxidation number of +4. The tutorial concludes with a summary of these findings.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the overall charge of a neutral compound like CF4?

Positive

Negative

Zero

Depends on the elements

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the oxidation number of fluorine in CF4?

+2

+1

0

-1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many fluorine atoms are present in CF4?

5

2

3

4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What must be the oxidation number of carbon in CF4 to maintain neutrality?

-4

+4

+2

0

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why does carbon have a positive oxidation number in CF4?

To balance the negative charges of fluorine

Because it is more electronegative than fluorine

To make the compound ionic

Because it is a metal