Balancing Chemical Reactions and Equations

The video tutorial explains how to balance a synthesis reaction involving strontium and oxygen to form strontium oxide. It begins by introducing the reaction and counting the atoms in the reactants and products. The tutorial then demonstrates how to balance the equation by adjusting coefficients, ensuring the number of atoms on both sides is equal. Finally, it identifies the states of matter for each compound involved in the reaction.

What type of reaction is described in the video involving strontium and oxygen?

• Double Replacement

• Single Replacement

• Decomposition

• Synthesis

How many oxygen atoms are present on the reactant side before balancing?

• Three

• Two

• Four

• One

What coefficient is placed in front of strontium oxide to balance the equation?

• Two

• Four

• Three

• One

What is the state of matter for strontium in the balanced equation?

• Gas

• Solid

• Aqueous

• Liquid

Which of the following is the correct balanced equation for the reaction?

• Sr + 2O2 → SrO2

• 2Sr + O2 → 2SrO

• 2Sr + 2O2 → 2SrO2

• Sr + O2 → SrO