Oxidation States and Ionic Compounds

The video tutorial explains how to determine the oxidation states of elements in the compound NaPF6. It covers two methods: analyzing the compound as a neutral entity and using the charge of the ion PF6-. The tutorial demonstrates that the oxidation numbers in a neutral compound add up to zero, while in an ion, they add up to the ion's charge. Sodium is identified as +1, fluorine as -1, and phosphorus as +5. The video concludes by summarizing these methods.

What is the overall charge of a neutral compound?

• Depends on the elements

• Negative

• Zero

• Positive

What is the oxidation state of sodium in NaPF6?

• +1

• +2

• -1

• 0

How many fluorine atoms are present in NaPF6?

• 4

• 5

• 6

• 7

What is the oxidation state of fluorine in NaPF6?

• -2

• -1

• +1

• 0

What is the oxidation state of phosphorus in NaPF6?

• +5

• +4

• +6

• +3

In the ion PF6-, what should the sum of oxidation states equal?

• 0

• -1

• +1

• +6

What is the charge on the ion PF6-?

• -2

• -1

• 0

• +1

Which method can be used to find the oxidation state of phosphorus in NaPF6?

• Using the charge of PF6-

• Using the charge of P+

• Using the charge of Na+

• Using the charge of F-