Oxidation States and Ion Charges

The video tutorial explains how to find the oxidation number for sulfur in the ion S2O4 2-. It begins by noting the ion's charge and how oxidation numbers add up to this charge. The tutorial then details the oxidation state of oxygen and sets up an equation to solve for sulfur's oxidation number, concluding that each sulfur atom has an oxidation state of +3.

What is the charge of the ion S2O4 2-?

• -1

• +2

• -2

• +1

How do oxidation numbers relate to the charge of an ion?

• They are always positive.

• They are equal to the number of atoms.

• They add up to the charge of the ion.

• They are always zero.

What is the typical oxidation number of oxygen in compounds?

• 0

• -2

• +1

• +2

In the ion S2O4 2-, what is the oxidation number of sulfur?

• -2

• +2

• -3

• +3

What equation is used to find the oxidation number of sulfur in S2O4 2-?

• x - 4 = 0

• x + 4 = 0

• 2x - 8 = -2

• 2x + 8 = -2

What is the result of dividing both sides of the equation by 2 in the calculation?

• x = 6

• x = 3

• x = -3

• x = -6

What is the oxidation state of each sulfur atom in S2O4 2-?

• +3

• -3

• -2

• +2

What is the final step in confirming the oxidation number of sulfur?

• Subtracting 8 from both sides

• Adding 8 to both sides

• Dividing by 2

• Multiplying by 2