Net Ionic Equations and Spectator Ions

The video tutorial explains how to write a balanced net ionic equation for the reaction between barium bromide (BaBr2) and sodium carbonate (Na2CO3). It begins by balancing the molecular equation, ensuring that the number of atoms for each element is equal on both sides. The tutorial then discusses the solubility of compounds, identifying barium carbonate as a precipitate. It proceeds to split strong electrolytes into ions for the complete ionic equation and identifies spectator ions to be removed. Finally, the net ionic equation is presented, with a focus on ensuring both charge and atom balance.

What is the first step in writing a net ionic equation?

• Identify the spectator ions.

• Balance the molecular equation.

• Determine the solubility of compounds.

• Write the complete ionic equation.

How do you balance the bromine atoms in the molecular equation?

• Add a coefficient of 2 in front of BaBr2.

• Add a coefficient of 2 in front of NaBr.

• Add a coefficient of 2 in front of Na2CO3.

• Add a coefficient of 2 in front of BaCO3.

Which of the following compounds is generally insoluble?

• Barium bromide

• Sodium carbonate

• Sodium bromide

• Barium carbonate

What is the state of barium carbonate in the reaction?

• Aqueous

• Gas

• Liquid

• Solid

What do you do with strong electrolytes in the complete ionic equation?

• Leave them as they are.

• Combine them into compounds.

• Convert them into gases.

• Split them into their ions.

Which ions are considered spectator ions in this reaction?

• Carbonate ions

• Bromide ions

• Barium ions

• Sodium ions

What is the role of spectator ions in a chemical reaction?

• They form the precipitate.

• They remain unchanged and do not participate.

• They change the state of the reaction.

• They participate in the reaction.

What is the net charge of the reactants in the net ionic equation?

• 1+

• 2+

• 2-

• 0

What must be balanced in the final net ionic equation?

• Only the atoms

• Only the charge

• Both atoms and charge

• Neither atoms nor charge

What is the final product of the reaction between barium bromide and sodium carbonate?

• Barium bromide

• Barium carbonate

• Sodium carbonate

• Sodium bromide