Hydration and Properties of Polyacrylate Beads

Hydration and Properties of Polyacrylate Beads

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explores the process of measuring how many water molecules attach to each polyacrylate molecule in water beads. It begins with a comparison to copper sulfate and magnesium sulfate, followed by data collection and initial mass calculations. The tutorial then delves into stoichiometry and molar mass to determine the number of water molecules attached to the beads. Final calculations reveal that approximately 10,000 water molecules are attached to each polyacrylate bead, highlighting the significant hydration capacity of these small molecules.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of the experiment described in the video?

To measure the number of water molecules attached to polyacrylate beads

To find the melting point of polyacrylate beads

To determine the density of polyacrylate beads

To compare the hydration levels of different salts

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many water molecules typically hydrate copper sulfate?

Five

Seven

Ten

Three

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What was the mass of 38 unhydrated polyacrylate beads?

0.18 grams

1.8 grams

0.47 grams

4.52 grams

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the mass per bead after hydration?

0.18 grams

0.197 grams

0.0047 grams

4.52 grams

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of the polyacrylate beads used in the experiment?

600

6000

600,000

60,000

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the unknown variable 'X' in the stoichiometry setup?

The number of water molecules attached

The density of the beads

The volume of water

The mass of the beads

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to calculate moles in the experiment?

Moles = mass x molar mass

Moles = mass / molar mass

Moles = molar mass / mass

Moles = mass + molar mass

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