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Redox Reactions and Titration Concepts

Redox Reactions and Titration Concepts

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Practice Problem

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains the process of redox titration of hydrogen peroxide using potassium permanganate as the titrant. It covers the observation of color changes during the reaction, the importance of stopping the titration at the right moment, and the steps to balance the redox reaction equations. The tutorial also details how to calculate molar ratios, determine the concentration of hydrogen peroxide, and find its mass percent in the solution.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of potassium permanganate in the experiment?

It acts as the analyte.

It is a solvent.

It is used as the titrant.

It is a catalyst.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What indicates the endpoint of the titration?

The solution turns green.

The solution turns blue.

The solution turns pink.

The solution becomes colorless.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is produced when permanganate reacts with hydrogen peroxide in an acidic medium?

Manganese and water

Manganese and oxygen gas

Oxygen gas and water

Hydrogen gas and water

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many electrons are involved in the half-reaction of permanganate?

Five electrons

Four electrons

Three electrons

Two electrons

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of balancing the redox reaction?

To calculate the density of the solution

To ensure mass and charge are conserved

To determine the endpoint of the titration

To ensure the reaction is spontaneous

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar ratio of permanganate to hydrogen peroxide?

3:5

1:1

2:3

2:5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the concentration of potassium permanganate used in the experiment?

0.04 M

0.08 M

0.02 M

0.06 M

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