Chemical Reactions and Laboratory Procedures

Chemical Reactions and Laboratory Procedures

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial demonstrates the process of making a salt from a soluble base (alkali) and an acid. It begins with measuring the alkaline using a volumetric pipet, followed by neutralizing it with hydrochloric acid using an indicator. The experiment is then repeated without the indicator to obtain a pure solution of sodium chloride. Finally, the water is evaporated to leave behind pure sodium chloride crystals.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in making a salt from a soluble base and an acid?

Adding an indicator

Mixing the acid and base directly

Heating the solution

Measuring the exact quantity of the alkaline

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to wear goggles during the experiment?

To avoid splashes from the corrosive alkaline

To prevent eye strain

To enhance visibility

To protect from harmful fumes

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of using a volumetric pipet in the experiment?

To add the indicator

To heat the solution

To measure an exact volume of the alkaline

To mix the acid and base

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What color does phenolphthalein turn in an alkaline solution?

Colorless

Bright pink

Green

Blue

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How much acid was required to neutralize the alkaline in the first experiment?

10.5 cm cubed

11.8 cm cubed

12.0 cm cubed

11.0 cm cubed

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the experiment repeated without the indicator?

To avoid contamination of the salt

To use less acid

To save time

To change the color of the solution

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the balanced chemical equation for the reaction?

H2O + NaCl → HCl + NaOH

HCl + NaOH → NaOH + H2O

NaCl + H2O → HCl + NaOH

HCl + NaOH → NaCl + H2O

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