What does Newton's Second Law state about the relationship between force, mass, and acceleration?

Newton's Laws and Friction Forces

Interactive Video
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Physics, Mathematics, Science
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9th - 12th Grade
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Hard

Patricia Brown
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Force is equal to mass times acceleration.
Force is equal to mass divided by acceleration.
Force is independent of mass and acceleration.
Force is equal to acceleration divided by mass.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the first example, what is the net force acting on the object if the applied force is 20 N and the friction force is 10 N?
10 N to the right
10 N to the left
30 N to the right
30 N to the left
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you calculate the acceleration of an object using Newton's Second Law?
Add the mass to the net force.
Multiply the net force by the mass.
Divide the net force by the mass.
Subtract the mass from the net force.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the second example, what does a constant velocity indicate about the forces acting on the object?
The forces are balanced.
The forces are unbalanced.
The object is accelerating.
There is no friction.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the friction force if the applied force is 8 N to the left and the object moves with constant velocity?
8 N to the left
16 N to the right
16 N to the left
8 N to the right
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the third example, how is the friction force calculated using the coefficient of friction?
Multiply the coefficient of friction by the normal force.
Subtract the coefficient of friction from the normal force.
Divide the coefficient of friction by the normal force.
Add the coefficient of friction to the normal force.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the role of the normal force in calculating the friction force?
It is multiplied by the coefficient of friction.
It is subtracted from the coefficient of friction.
It is added to the coefficient of friction.
It is divided by the coefficient of friction.
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