Mixing Solutions: Solving Acid Concentration Problems

The video tutorial explains how to create a 15% acid solution by mixing 10% and 35% solutions. It introduces the problem, defines variables, sets up equations, and demonstrates solving the system of equations using substitution. The final solution involves calculating the exact amounts of each solution needed.

What is the main goal of the chemist in this problem?

• To create a 20% acid solution

• To create a 15% acid solution

• To create a 35% acid solution

• To create a 10% acid solution

What do the variables X and Y represent in this problem?

• X is the amount of 35% solution, Y is the amount of 10% solution

• X is the concentration, Y is the total amount of solution

• X is the amount of 10% solution, Y is the amount of 35% solution

• X is the total amount of solution, Y is the concentration

What is the first equation derived from the problem?

• X + Y = 15

• X - Y = 15

• X + Y = 2

• X - Y = 2

How is the second equation transformed to eliminate decimals?

• By multiplying everything by 100

• By dividing everything by 10

• By dividing everything by 100

• By multiplying everything by 10

What is the transformed second equation after eliminating decimals?

• X + Y = 15

• X + Y = 30

• 10X + 35Y = 30

• 10X + 35Y = 15

What method is used to solve the system of equations?

• Trial and error

• Elimination or substitution

• Matrix method

• Graphical method

What is the value of Y after solving the equations?

• 4/5

• 1/5

• 3/5

• 2/5

What is the value of X after solving the equations?

• 1 2/5

• 1 3/5

• 1 4/5

• 1 1/5

What is the decimal equivalent of 3/5?

• 0.6

• 0.3

• 0.5

• 0.4

How many liters of the 35% solution are needed in the final mixture?

• 0.3 liters

• 0.5 liters

• 0.2 liters

• 0.4 liters