What is the primary challenge in calculating the density of irregularly shaped objects?

Calculating Density Through Water Displacement and Volume Relationships

Interactive Video
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Physics, Science, Mathematics
•
9th - 10th Grade
•
Hard

Patricia Brown
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Their mass is difficult to measure.
Their volume cannot be calculated using simple dimensions.
They are too small to measure accurately.
They have a uniform density.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the relationship between milliliters and cubic centimeters?
1 milliliter is equal to 10 cubic centimeters.
1 milliliter is equal to 100 cubic centimeters.
1 milliliter is equal to 1 cubic centimeter.
1 milliliter is equal to 0.1 cubic centimeters.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the volume of an irregular object like a rock determined using water?
By using a ruler to measure the rock's dimensions.
By observing the change in water level when the rock is submerged.
By calculating the surface area of the rock.
By measuring the weight of the water.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If a rock displaces 35 milliliters of water, what is its volume in cubic centimeters?
35 cubic centimeters
3.5 cubic centimeters
350 cubic centimeters
0.35 cubic centimeters
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the formula for calculating density?
Density = Volume - Mass
Density = Mass x Volume
Density = Mass / Volume
Density = Volume / Mass
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the example, what is the mass of the rock used to calculate density?
400 grams
200 grams
100 grams
300 grams
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the calculated density of the rock in the example?
9.57 grams per milliliter
8.57 grams per milliliter
7.57 grams per milliliter
6.57 grams per milliliter
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