Step by step process explaining completing the square to solve

Step by step process explaining completing the square to solve

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Quizizz Content

FREE Resource

The video tutorial guides students through solving a quadratic equation by completing the square. It begins with setting up the problem and isolating variables. The process involves creating a perfect square trinomial, factoring it, and using inverse operations to solve the equation. The tutorial emphasizes understanding each step and applying the method to find the solution.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't the equation v^2 + 10v - 21 be factored directly?

The equation is not quadratic

The equation has no real roots

The equation is already in its simplest form

There are no two numbers that multiply to -21 and add to 10

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving a quadratic equation by completing the square?

Finding the square root

Isolating the variable

Factoring the equation

Isolating the constant term

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of B/2 squared in the equation v^2 + 10v - 21?

5

10

25

50

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of adding the same value to both sides of the equation?

To simplify the equation

To factor the equation

To balance the equation

To eliminate the variable

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the expression (v + 5)^2 derived from the equation?

By adding 5 to both sides

By factoring v^2 + 10v + 25

By multiplying v by 5

By subtracting 5 from both sides

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is used to solve for v after rewriting the equation as (v + 5)^2 = 46?

Square root

Subtraction

Addition

Multiplication

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final solution for v in the equation v^2 + 10v - 21 = 0?

v = -5 ± sqrt(21)

v = 5 ± sqrt(21)

v = -5 ± sqrt(46)

v = 5 ± sqrt(46)