From 0 to 1 Data Structures & Algorithms in Java - Dealing With Negative Cycles In The Bellman Ford Algorithm

From 0 to 1 Data Structures & Algorithms in Java - Dealing With Negative Cycles In The Bellman Ford Algorithm

Assessment

Interactive Video

Information Technology (IT), Architecture, Physics, Science

University

Hard

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The video tutorial explains the concept of negative cycles in graphs and their impact on shortest path calculations. It introduces the Bellman Ford algorithm, which can handle graphs with negative weighted edges. The tutorial provides an example of a negative cycle and demonstrates how it affects path calculations. It also explains how to detect negative cycles using the Bellman Ford algorithm and discusses the algorithm's complexity in terms of edge and vertex traversal.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a negative cycle in a graph?

A cycle with all positive edge weights

A cycle with no edges

A cycle with equal positive and negative edge weights

A cycle with a total negative edge weight

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it difficult to find the shortest path in a graph with a negative cycle?

Because negative cycles make the graph disconnected

Because negative cycles allow for infinitely decreasing path lengths

Because negative cycles increase the path length

Because negative cycles create multiple shortest paths

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the Bellman-Ford algorithm detect a negative cycle?

By comparing the graph to a known cycle-free graph

By counting the number of edges in the graph

By performing an additional iteration after V-1 relaxations

By checking if all vertices have been visited

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens if a vertex's distance is updated after V-1 iterations in Bellman-Ford?

The graph is acyclic

The graph has a negative cycle

The graph has a positive cycle

The graph is disconnected

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the time complexity of the Bellman-Ford algorithm using adjacency lists?

O(EV)

O(E^2)

O(V^2)

O(V^3)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the time complexity change when using an adjacency matrix?

It becomes O(E^2)

It remains O(EV)

It becomes O(V^3)

It becomes O(V^2)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is E equal to V^2 in an adjacency matrix?

Because the graph is a cycle

Because the graph is a tree

Because there are no edges in the graph

Because every vertex is connected to every other vertex