Modeling Exponential Growth with Two Variable Equations

Modeling Exponential Growth with Two Variable Equations

Assessment

Interactive Video

Mathematics, Biology

1st - 6th Grade

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

The video tutorial explains how to represent repeated multiplication using exponents, using examples of bacterial and viral growth to illustrate exponential growth. It introduces the concept of initial value and growth factor, and demonstrates how to model these situations with equations. The tutorial covers how to generalize exponential growth for any number of time periods.

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7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you express the multiplication of five 2's using exponents?

2 to the power of 10

10 to the power of 2

2 to the power of 5

5 to the power of 2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a bacteria population doubles every hour, how many bacteria will there be after 3 hours if you start with 25?

50

100

200

400

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the shorthand expression for multiplying 4983 by 2 nine times?

4983 times 9 to the 3rd power

4983 times 2 to the 9th power

4983 times 9 to the 2nd power

4983 times 2 to the 8th power

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the formula y = 4983 * 2^x, what does x represent?

The initial number of bacteria

The growth factor

The final number of bacteria

The number of hours

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial value in the exponential growth equation for a virus that triples every hour starting with 30 specimens?

300

90

30

3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the growth factor in the exponential growth equation for a virus that triples every hour?

3

90

2

30

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How would you model an exponential growth situation where a quantity triples every time period?

y = initial value * 2^x

y = initial value * 3^x

y = initial value * x^3

y = initial value * 3x

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