Evaluate with a Variable the Composition of Two Functions

The video tutorial explains how to solve a mathematical problem involving the function H of X, which is defined as X^2 + 6X + 8. The instructor demonstrates how to substitute 3A into the function to find H of 3A, and then further simplifies the expression. The process involves substituting H of 3A into another function, F of X = 5X, and applying the distributive property to reach the final answer. The tutorial emphasizes understanding the substitution process and simplification techniques.

What is the expression for H(3A) when H(x) = x^2 + 6x + 8?

• 9A^2 + 6A + 8

• 3A^2 + 6*3A + 8

• 9A^2 + 18A + 8

• 3A^2 + 18A + 8

How do you substitute H(3A) into F(x) = 5x?

• Replace x with 5A

• Replace x with 3A

• Replace x with H(3A)

• Replace x with 3A^2

What is the expression for F(H(3A)) before applying the distributive property?

• 5 * (9A^2 + 18A + 8)

• 5 * (3A^2 + 6A + 8)

• 5 * (9A^2 + 6A + 8)

• 5 * (3A^2 + 18A + 8)

What is the result of applying the distributive property to 5 * (9A^2 + 18A + 8)?

• 45A^2 + 90A + 40

• 45A^2 + 18A + 40

• 45A^2 + 90A + 8

• 45A^2 + 18A + 8

What is the final simplified expression for F(H(3A))?

• 45A^2 + 18A + 8

• 45A^2 + 90A + 8

• 45A^2 + 90A + 40

• 45A^2 + 18A + 40