Second Moment of Area Example 4 (I beam)

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Physics
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10th - 12th Grade
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Hard
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7 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main reason the instructor advises against using calculus for this problem?
The shape is complex and not friendly for calculus.
The instructor prefers using calculus for simpler shapes.
Calculus is not accurate for this problem.
The shape is too simple for calculus.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which formula is used to calculate the second moment of area for a rectangle at its centroid?
Base times height squared
One on twelve base times height cubed
Base times height cubed
One on twelve base times height squared
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the parallel axis theorem help to determine?
The second moment of area about a parallel axis
The centroid of a shape
The area of a rectangle
The distance between two axes
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the I-beam deconstructed for the calculation?
Into one large square
Into four circles
Into three rectangles
Into two triangles
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is the parallel axis theorem not needed for the blue rectangle?
The blue rectangle is symmetrical.
The axis of the blue rectangle is already at the centroid.
The blue rectangle is not part of the I-beam.
The blue rectangle is too small.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final result of the second moment of area for the I-beam?
4.52 * 10^8 millimeters to the power of four
5.42 * 10^8 millimeters to the power of four
5.42 * 10^6 millimeters to the power of four
4.52 * 10^6 millimeters to the power of four
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of summing the second moments of area for the three rectangles?
To find the height of the I-beam
To calculate the total second moment of area for the I-beam
To determine the weight of the I-beam
To find the total area of the I-beam
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