Solving Simultaneous Equations with Algebraic Techniques

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Mathematics
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10th - 12th Grade
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Hard
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in solving the given simultaneous equations?
Apply the quadratic formula
Substitute the linear equation into the nonlinear equation
Collect like terms
Expand the quadratic equation
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When expanding the expression (2y - 3)^2, what is the result?
4y^2 + 12y + 9
4y^2 - 6y + 9
4y^2 - 12y + 9
4y^2 - 12y - 9
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
After expanding and simplifying, what is the quadratic equation obtained?
11y^2 - 24y + 18 = 0
8y^2 - 24y + 18 = 0
11y^2 - 24y + 18 = 14
11y^2 - 24y + 4 = 0
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the values of a, b, and c in the quadratic equation 11y^2 - 24y + 4 = 0?
a = 11, b = -24, c = 4
a = 11, b = 24, c = 4
a = 11, b = 24, c = 18
a = 11, b = -24, c = 18
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the quadratic formula used to solve the equation?
x = (b ± √(b^2 - 4ac)) / 2a
x = (-b ± √(b^2 - 4ac)) / 2a
x = (b ± √(b^2 + 4ac)) / 2a
x = (-b ± √(b^2 + 4ac)) / 2a
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the two possible values of y obtained from the quadratic formula?
y = 2/11 and y = 2
y = 2/11 and y = 3
y = 1/11 and y = 2
y = 2 and y = 3
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If y = 2/11, what is the corresponding value of x?
x = 1
x = -29/11
x = 2
x = 29/11
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