GCSE Secondary Maths Age 13-17 - Ratio, Proportion & Rates of Change: Inverse Proportionality - Explained

The video tutorial explains the concept of inverse and direct proportions, focusing on solving a problem where P is inversely proportional to T. The teacher demonstrates how to find the constant K using given values and then uses this constant to solve for P when T equals 6. The tutorial also provides insights into the teaching approach and offers tips on how to tackle such questions in exams, highlighting the importance of understanding the formula and calculation of K.

If P is inversely proportional to T, what happens to P when T increases?

• P becomes zero

• P decreases

• P remains constant

• P increases

What is the first step in solving an inverse proportion problem?

• Subtract the variables

• Divide the variables

• Multiply the variables and set equal to a constant

• Add the variables

In the context of inverse proportion, what does the constant K represent?

• The difference between the variables

• The sum of the variables

• The ratio of the variables

• The product of the variables

How do you find the value of P when T is given, using the constant K?

• Subtract T from K

• Divide K by T

• Multiply K by T

• Add K to T

How many marks are awarded for correctly solving the inverse proportion problem?

• Four marks

• Two marks

• One mark

• Three marks