Implicit Differentiation Techniques

The video tutorial covers implicit differentiation, a concept that often confuses learners. It begins with an introduction to the topic and a setup of the first problem, which involves taking derivatives using the product and chain rules. The instructor provides a detailed walkthrough of the solution, emphasizing the importance of understanding the chain rule. The solution is then simplified. The second problem is introduced and solved similarly, with a focus on applying the chain rule and simplifying the result. The tutorial aims to clarify the process of implicit differentiation and improve understanding.

What is the initial step in solving an implicit differentiation problem?

• Take the derivative of both sides with respect to y.

• Take the derivative of both sides with respect to x.

• Integrate both sides with respect to x.

• Solve for y in terms of x.

Which rule is used to differentiate the product xy in the given function?

• Power Rule

• Quotient Rule

• Chain Rule

• Product Rule

What is the derivative of y with respect to x often represented as?

• x'

• d/dx

• dx/dy

• y'

In the simplification process, what is done with terms that do not contain y'?

• They are multiplied by y'.

• They are divided by y'.

• They are moved to the right side of the equation.

• They are moved to the left side of the equation.

What is the final expression for dy/dx in the first problem?

• (2y - 2x) / (2y - 2x - 8)

• (8y - 48) / (2x - 2y)

• (24y - 2x + 400) / (32y - 24x - 300)

• (12y - x + 200) / (16y - 12x - 150)

What is the implicit function given in the second problem?

• x^2 - 24xy + 16y^2 = 0

• x - y^2 = 8(y - 6)

• x^3 - 3xy + y^3 = 0

• x^2 + y^2 = 1

What is the derivative of x with respect to x?

• 0

• 1

• x

• y

How is the derivative of 8y with respect to x calculated?

• By using the power rule

• By using the quotient rule

• By using the chain rule

• By using the product rule

What is the final expression for dy/dx in the second problem?

• (y - x) / (y - x - 8)

• (2y - 2x) / (2y - 2x - 8)

• (8y - 48) / (2x - 2y)

• (12y - x + 200) / (16y - 12x - 150)

Tags

CCSS.HSA.APR.D.6

What is the purpose of dividing the numerator and denominator by 2 in the final step?

• To find the integral

• To simplify the expression

• To eliminate y

• To eliminate x

Tags

CCSS.HSA.APR.D.6