What does the Extreme Value Theorem guarantee for a continuous function over a closed interval?

Understanding the Extreme Value Theorem

Interactive Video
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Mathematics
•
9th - 12th Grade
•
Hard

Amelia Wright
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
It guarantees a local maximum and minimum.
It guarantees only an absolute maximum.
It guarantees an absolute maximum and minimum.
It guarantees only an absolute minimum.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the logical symbol used to denote 'there exists' in the context of the theorem?
∀
∅
∃
∈
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the illustration of the theorem, what do the points c and d represent?
They are the endpoints of the interval.
They are the points where the function has its absolute minimum and maximum.
They are arbitrary points on the graph.
They are the points where the function is undefined.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it important for the function to be continuous in the Extreme Value Theorem?
To ensure the function is differentiable.
To ensure the function is increasing.
To ensure the function has no gaps or jumps.
To ensure the function is decreasing.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why might it be difficult to identify a maximum or minimum in a non-continuous function?
Because the function may have gaps or jumps.
Because the function is linear.
Because the function is always decreasing.
Because the function is always increasing.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the context of the Extreme Value Theorem, what is the significance of a closed interval?
It includes the endpoints, allowing them to be considered for maximum and minimum values.
It ensures the function is differentiable.
It excludes the endpoints, focusing only on the interior points.
It ensures the function is continuous.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens if the interval is open in the context of the Extreme Value Theorem?
The theorem still holds true.
The endpoints cannot be considered for maximum and minimum values.
The function becomes discontinuous.
The function becomes non-differentiable.
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