What is the purpose of breaking down a quadratic approximation into constant, linear, and quadratic terms?

Quadratic Approximations and Derivatives

Interactive Video
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Mathematics
•
11th Grade - University
•
Hard

Mia Campbell
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
To simplify the calculation process
To make the function more complex
To eliminate variables
To avoid using derivatives
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the given example, what is the function f(x, y) used for approximation?
e^x * cos(y)
e^(x/2) * sin(y)
x^2 + y^2
sin(x) * cos(y)
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the derivative of e^(x/2) with respect to x?
x * e^(x/2)
1/2 * e^(x/2)
2 * e^(x/2)
e^(x/2)
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When evaluating the partial derivative with respect to y, what is the derivative of sin(y)?
sin(y)
-cos(y)
cos(y)
-sin(y)
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of the mixed partial derivative at the point (0, π/2)?
1/2
-1
0
1
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first term in the quadratic approximation of the function?
The quadratic term
The constant term
The linear term
The mixed term
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the quadratic approximation simplified in terms of x and y?
x and y
x^2 and y^2
x^2/8 and -1/2(y - π/2)^2
x/2 and y/2
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