Understanding Derivatives of Logarithmic Functions

Understanding Derivatives of Logarithmic Functions

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Sophia Harris

FREE Resource

The video tutorial explains how to find the derivative of a function F of X, which is the natural log of X plus five over X minus one. It presents two methods: an easy way using logarithm properties to simplify the expression before differentiating, and a hard way using the chain and product rules without simplification. Both methods ultimately yield the same result, demonstrating the effectiveness of simplification in calculus.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main objective when analyzing the function F(x) in the video?

To solve F(x) for x

To find the integral of F(x)

To determine the limit of F(x) as x approaches infinity

To calculate the derivative F'(x)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which property of logarithms is used in the easy method to simplify the expression?

Change of base formula

Logarithm of a power

Logarithm of a quotient

Logarithm of a product

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the easy method, what is the derivative of ln(x + 5) with respect to x?

1/(x + 5)

x/(x + 5)

ln(x + 5)

x + 5

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main challenge of the hard method compared to the easy method?

It involves complex logarithm properties

It uses the chain rule without simplification

It requires integration

It needs numerical approximation

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the hard method, what is the reciprocal of the expression X + 5 over X - 1?

X - 1 over X + 5

1 over X - 1

1 over X + 5

X + 5 over X - 1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which rule is applied in the hard method to differentiate the expression X + 5 times X - 1 to the negative one power?

Power rule

Product rule

Sum rule

Quotient rule

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the expression when the product rule is applied in the hard method?

It becomes more complex

It remains unchanged

It simplifies to a constant

It results in a simpler expression

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