What happens to the numerator x^2 + 1 as x approaches infinity?

Understanding Limits and Oscillations

Interactive Video
•
Mathematics, Science
•
11th Grade - University
•
Hard

Amelia Wright
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
It approaches infinity.
It remains constant.
It approaches zero.
It oscillates between -1 and 1.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the range of values that sin(x) oscillates between?
-2 and 2
-1 and 1
0 and 1
0 and infinity
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following best describes the behavior of sin(x) as x increases?
It remains constant.
It decreases without bound.
It oscillates between -1 and 1.
It increases without bound.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can't we conclude that the limit of (x^2 + 1) / sin(x) goes to infinity?
Because the denominator is constant.
Because the numerator is bounded.
Because the denominator oscillates between positive and negative values.
Because the numerator oscillates.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the primary challenge in determining the limit of (x^2 + 1) / sin(x)?
The function is not continuous.
The oscillating nature of the denominator.
The denominator is zero.
The numerator is too complex.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens when sin(x) equals zero in the function (x^2 + 1) / sin(x)?
The function becomes undefined.
The function approaches infinity.
The function becomes zero.
The function remains constant.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the effect of vertical asymptotes on the function (x^2 + 1) / sin(x)?
They make the function constant.
They have no effect on the function.
They cause the function to oscillate more.
They make the function undefined at certain points.
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