AP Calculus AB 2015: Derivatives and Quotient Rule

AP Calculus AB 2015: Derivatives and Quotient Rule

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial addresses a calculus problem from the 2015 AP Calculus AB test, focusing on evaluating the second derivative of a given curve at a specific point. The instructor skips parts A and B, directly tackling part C, which involves using the quotient rule to find the second derivative. The process includes calculating the first derivative, applying the quotient rule, and evaluating the expression at the point where x equals -1 and y equals 1. The tutorial concludes with the simplification of the expression to arrive at the final result.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of the curve discussed in the problem?

y^3 - xy = 2

y^2 - x^2 = 2

y^3 + xy = 2

y^2 + xy = 2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the task given in part c of the problem?

Determine the maximum value of the function

Find the equation of the tangent line

Evaluate the second derivative at a point

Evaluate the first derivative at a point

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which rule is suggested as the best approach for finding the second derivative?

Power Rule

Quotient Rule

Chain Rule

Product Rule

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of 3y^2 with respect to x?

6y

6y * dy/dx

3y

3y * dy/dx

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of dy/dx at the point where x = -1 and y = 1?

1/3

1/2

1/4

1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for the second derivative of y with respect to x?

y * (3y^2 - x) / (dy/dx)

y / (3y^2 - x)

(dy/dx) * (3y^2 - x) - y * (6y * dy/dx - 1) / (3y^2 - x)^2

(dy/dx) * (3y^2 - x) + y * (6y * dy/dx - 1) / (3y^2 - x)^2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the second derivative at the point (x, y) = (-1, 1)?

1/16

1/8

1/32

1/4

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