Calculus Applications in Business and Economics

Calculus Applications in Business and Economics

Assessment

Interactive Video

Mathematics, Business

10th - 12th Grade

Hard

Created by

Mia Campbell

FREE Resource

The video tutorial focuses on solving maximum and minimum problems using calculus, particularly in business and economics contexts. It provides guidelines for approaching these problems, such as reading carefully, listing variables, and translating problems into equations. Two examples are discussed: minimizing a quadratic function with constraints and maximizing the volume of a box formed by cutting squares from a cardboard sheet. The tutorial demonstrates using derivatives to find critical points and verify maxima or minima through second derivatives.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving maximum and minimum problems using calculus?

Draw a graph of the function

Read the problem carefully and make a sketch if possible

Find the derivative of the function

Set the function equal to zero

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example problem, what is the constraint given for minimizing Q?

X + Y = 5

X * Y = 5

X - Y = 5

X + Y = 10

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you rewrite the equation Q = 2X^2 + 3Y^2 in terms of one variable?

Substitute Y with X

Substitute X with 5 - Y

Substitute X with Y

Substitute Y with 5 - X

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the critical number found when minimizing Q?

X = 5

X = 2

X = 3

X = 0

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the shape of the cardboard used in the box volume problem?

Square

Triangle

Circle

Rectangle

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the volume of the box in the example problem?

Length / Width / Height

Length + Width + Height

Length x Width x Height

Length - Width - Height

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the critical number for maximizing the volume of the box?

X = 5

X = 5/3

X = 3

X = 2

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