Understanding Demand Functions

Understanding Demand Functions

Assessment

Interactive Video

Mathematics, Business

10th - 12th Grade

Hard

Created by

Mia Campbell

FREE Resource

The video tutorial explains a demand function D(Q) = -Q^2 - 2Q + 517, where Q is in thousands of units sold and D(Q) is the price per unit. It covers three main problems: calculating the price for 7,000 units sold, determining the number of units sold at a price of $374, and finding the value of Q where D(Q) crosses the Q-axis. The tutorial uses algebraic manipulation and the quadratic formula to solve these problems, emphasizing the importance of understanding the units and the mathematical process involved.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the variable Q represent in the demand function?

The price per unit in dollars

The total revenue

The cost of production

The number of units sold in thousands

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If 7,000 units are to be sold, what is the value of Q used in the demand function?

7,000

0.007

70

7

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the price per unit if 7,000 units are sold?

$143

$517

$374

$454

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When the price is set at $374, what equation do we solve to find Q?

D(Q) = 374

Q = 374

D(Q) = -Q^2 + 2Q - 517

374 = -Q^2 - 2Q + 517

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many units can be expected to sell if the price is $374?

7,000 units

11,000 units

21,760 units

13,000 units

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What method is used to find where the demand function crosses the Q-axis?

Linear approximation

Quadratic formula

Graphical method

Trial and error

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the demand function crossing the Q-axis?

It marks the minimum cost

It shows the break-even point

It indicates the maximum price

It represents the quantity demanded when the price is zero

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