
Differential Equations Concepts Review

Interactive Video
•
Mathematics
•
10th - 12th Grade
•
Hard
Standards-aligned

Olivia Brooks
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What type of differential equation is being solved in this tutorial?
Linear third-order with constant coefficients
Linear first-order with variable coefficients
Non-linear second-order with constant coefficients
Linear second-order with constant coefficients
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the form of the characteristic equation used to solve the differential equation?
a r^2 + br + c = 0
a r + b = 0
a r^3 + br^2 + c = 0
a r^2 + b = 0
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the roots of the characteristic equation when the coefficients are a=1, b=0, and c=25?
0 and 25
1 and -1
5i and -5i
5 and -5
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the general solution form when the characteristic equation has complex roots?
y(t) = c1 e^(alpha t) + c2 e^(-alpha t)
y(t) = c1 e^(beta t) + c2 e^(-beta t)
y(t) = c1 cos(beta t) + c2 sin(beta t)
y(t) = c1 e^(alpha t) cos(beta t) + c2 e^(alpha t) sin(beta t)
Tags
CCSS.HSF.TF.A.2
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of c2 when y(pi/10) = -4?
2
4
-4
0
Tags
CCSS.HSF.TF.A.2
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of c1 when y'(pi/10) = -20?
-4
0
4
2
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the particular solution for the given initial conditions?
y(t) = -4 cos(5t) - 4 sin(5t)
y(t) = -4 cos(5t) + 4 sin(5t)
y(t) = 4 cos(5t) - 4 sin(5t)
y(t) = 4 cos(5t) + 4 sin(5t)
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