Solving Equations with Fractions

The video tutorial explains how to solve the equation x plus nine-halves equals nine-eighths by isolating the variable x. It involves subtracting nine-halves from both sides, finding a common denominator, and simplifying the fractions. The solution is verified by substituting back into the original equation to ensure both sides are equal.

What is the initial equation we are trying to solve?

• x + 9/2 = 9/8

• x - 9/2 = 9/8

• x + 8/9 = 9/2

• x - 8/9 = 9/2

Tags

CCSS.HSA.REI.A.1

What operation is performed to both sides of the equation to isolate x?

• Subtract 9/2

• Add 9/2

• Divide by 9/2

• Multiply by 9/2

Tags

CCSS.6.EE.B.7

What is the purpose of performing the same operation on both sides of an equation?

• To simplify the equation

• To maintain equality

• To change the equation

• To make the equation more complex

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

Why do we need a common denominator when subtracting fractions?

• To simplify the equation

• To ensure the fractions have the same base for subtraction

• To make the equation more complex

• To change the fractions to whole numbers

What is the least common denominator used in this problem?

• 8

• 6

• 4

• 2

Tags

CCSS.7.NS.A.1C

What is the result of subtracting 9/2 from 9/8?

• -18/8

• 18/8

• -27/8

• 27/8

Tags

CCSS.6.EE.B.7

What is the solution to the equation x + 9/2 = 9/8?

• x = 27/8

• x = -27/8

• x = 9/8

• x = -9/8

Tags

CCSS.8.EE.C.7B

How do we verify the solution x = -27/8?

• By using a calculator

• By substituting x = -27/8 back into the original equation

• By solving a different equation

• By graphing the equation

Tags

CCSS.8.EE.A.2

What is the result of substituting x = -27/8 back into the equation?

• The left side equals 27/8

• The left side equals -9/8

• The left side equals 0

• The left side equals 9/8

Tags

CCSS.7.EE.B.4A

What is the final step in solving the equation?

• Dividing fractions

• Multiplying fractions

• Adding fractions

• Checking the solution by substitution

Tags

CCSS.7.EE.B.4A