What is the initial challenge when trying to determine the limit using direct substitution?

Understanding Limits and Algebraic Techniques

Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Hard

Emma Peterson
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The limit is always zero.
The limit is undefined.
The limit results in an indeterminate form.
The limit is always infinite.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of finding a common denominator when simplifying fractions?
To make the fractions larger.
To eliminate the fractions.
To simplify the expression and resolve indeterminate forms.
To change the variable.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why do we multiply by the conjugate in algebraic simplification?
To change the variable.
To simplify the expression and eliminate discontinuities.
To eliminate the square root.
To increase the value of the expression.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens to the expression after simplifying by removing the common factor of x?
The expression becomes zero.
The expression becomes more complex.
The removable discontinuity is eliminated.
The expression becomes undefined.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final value of the limit after simplification and direct substitution?
Negative 5
Negative 2.5
Zero
Positive 2.5
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How can we verify the results of the limit evaluation?
By guessing the value.
By using a table of values and graph.
By using a different variable.
By using a calculator.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the table of values show as x approaches zero from the left?
The function values approach zero.
The function values approach positive 2.5.
The function values remain constant.
The function values approach negative 2.5.
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