Improper Integrals and Financial Applications

Improper Integrals and Financial Applications

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Lucas Foster

FREE Resource

This video tutorial covers improper integrals, focusing on determining their convergence or divergence. It includes examples of calculating areas under curves, such as y = 2/x^2, and discusses the criteria for convergence. The tutorial also explores divergent integrals, decreasing functions, and the use of substitution in convergent integrals. Finally, it applies these concepts to finance, explaining the accumulated present value of a continuous money flow.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal of studying improper integrals?

To calculate derivatives

To solve differential equations

To determine convergence or divergence

To find the area under a curve

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you handle an improper integral with an infinite upper limit?

Ignore the infinite limit

Replace the upper limit with a variable and take the limit

Use numerical methods

Use a finite upper limit

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does it mean if an improper integral is divergent?

The integral has a finite value

The integral does not exist

The integral is equal to zero

The integral is negative

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which function's improper integral is divergent due to its increasing nature?

y = ln(x)

y = 1/x

y = x^2

y = e^x

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of the improper integral of a decreasing function that converges?

The area is undefined

The area is finite

The area is zero

The area is infinite

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is used for the integral involving e^(-2x)?

u = x^2

u = -2x

u = ln(x)

u = 1/x

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the accumulated present value of a perpetual money flow?

P / K

P - K

P + K

P * K

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