Solving Linear Equations with Decimals

The video tutorial explains how to solve the equation -1.5x = -0.6 by isolating the variable x. It involves dividing both sides by -1.5, simplifying the equation, and calculating the quotient. The solution is verified by substituting the value back into the original equation to ensure it satisfies the equation.

What is the initial equation we are trying to solve?

• 1.5x = 0.6

• -1.5x = -0.6

• -1.5x = 0.6

• 1.5x = -0.6

Tags

CCSS.HSA.REI.A.1

What operation is used to isolate x in the equation?

• Division

• Multiplication

• Subtraction

• Addition

Tags

CCSS.HSA.REI.A.1

Why do we divide both sides of the equation by -1.5?

• To make the equation more complex

• To change the sign of x

• To cancel out the multiplication by -1.5

• To add a constant to both sides

Tags

CCSS.7.NS.A.2A

CCSS.7.NS.A.2B

What is the result of dividing -1.5 by -1.5?

• 2

• -1

• 1

• 0

Tags

CCSS.5.NBT.B.7

What is the quotient of 0.6 divided by 1.5?

• 0.2

• 0.4

• 0.3

• 0.5

Tags

CCSS.5.NBT.B.7

How do we handle decimals when dividing 0.6 by 1.5?

• Multiply both by 10 to make the divisor a whole number

• Add zeros to the dividend

• Ignore the decimals

• Subtract decimals from both numbers

Tags

CCSS.7.EE.B.4A

What is the final solution for x in the equation?

• x = 0.3

• x = 0.4

• x = 0.5

• x = 0.2

Tags

CCSS.6.EE.B.5

How do we verify the solution of the equation?

• By substituting the solution back into the original equation

• By multiplying the solution by 2

• By dividing the solution by 2

• By adding the solution to both sides

Tags

CCSS.6.EE.A.2C

What is the result of substituting 0.4 for x in the original equation?

• 0.4

• -0.4

• -0.6

• 0.6

Tags

CCSS.8.EE.C.7B

What does the verification step confirm about the solution?

• The solution is incorrect

• The solution is approximate

• The solution is correct

• The solution needs adjustment

Tags

CCSS.8.EE.C.7B