Understanding Water Flow in a Conic Tank

Understanding Water Flow in a Conic Tank

Assessment

Interactive Video

Mathematics, Science

9th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to solve a problem involving water leaking from an inverted conic tank while water is being pumped in. It covers unit conversion, using the volume formula for a cone, and applying similar triangles to relate dimensions. The tutorial demonstrates differentiating the volume formula to find rates of change and concludes with calculating the rate at which water is pumped into the tank.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the rate at which water is leaking from the tank?

8,200 cubic centimeters per minute

4 cubic centimeters per minute

24 cubic centimeters per minute

13 cubic centimeters per minute

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the height of the tank in centimeters?

1,300 centimeters

1,500 centimeters

200 centimeters

400 centimeters

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it necessary to convert meters to centimeters in this problem?

To simplify the problem

To match the volume formula

To make calculations easier

To ensure all measurements are in the same unit

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What formula is used to calculate the volume of the conic tank?

V = π r² h

V = 1/2 π r² h

V = 2/3 π r² h

V = 1/3 π r² h

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How are similar triangles used in this problem?

To calculate the volume of the tank

To find the diameter of the tank

To determine the rate of water leakage

To relate the radius and height of the water level

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between r and h derived from similar triangles?

r = (2/13)h

r = (13/2)h

r = (2/3)h

r = (1/2)h

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of the volume formula with respect to time?

dv/dt = 1/2 π r² dr/dt

dv/dt = 2/3 π r² dr/dt

dv/dt = 1/3 π r² dr/dt

dv/dt = 13/6 π r² dr/dt

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