

Calculating the Area of a Region Enclosed by Curves
Interactive Video
•
Mathematics
•
10th - 12th Grade
•
Practice Problem
•
Hard
Standards-aligned
Amelia Wright
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in solving the problem of finding the area enclosed by the curves?
Use numerical methods
Find the derivative of the functions
Directly calculate the area
Sketch the region and decide the integration variable
Tags
CCSS.HSF.TF.B.7
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which functions bound the region from above and below?
y = 9 cosine X and y = 25 tangent X
y = 9 sine X and y = 25 cosine X
y = 25 secant 2x and y = 9 cosine X
y = 25 secant X and y = 9 sine X
Tags
CCSS.8.F.A.1
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can the integration be simplified by using symmetry?
The region is symmetrical about the X-axis
The region is symmetrical about the Y-axis
The region is symmetrical about the line y = x
The region is symmetrical about the origin
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of the symmetry in this problem?
It allows us to integrate over the entire range
It allows us to integrate over half the range and double the result
It changes the integration variable
It simplifies the derivative calculation
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the antiderivative of 25 secant 2x?
25 sine x
25 cosine x
25 tangent x
25 cotangent x
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the antiderivative of 9 cosine X?
9 secant X
9 tangent X
9 cotangent X
9 sine X
Tags
CCSS.HSF.TF.A.2
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of finding the antiderivative in this context?
To find the area under the curve
To calculate the volume of the region
To solve a differential equation
To determine the slope of the curve
Tags
CCSS.HSF.TF.A.2
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