What is the initial condition given for the differential equation Y' = y^3?

Differential Equations and Initial Conditions

Interactive Video
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Mathematics
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10th - 12th Grade
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Hard

Amelia Wright
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
y(0) = 0
y(0) = 1
y(1) = 1
y(1) = 0
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which theorem is used to rewrite the differential equation in terms of DX/Dy?
Pythagorean Theorem
Mean Value Theorem
Inverse Function Theorem
Fundamental Theorem of Calculus
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the general solution form obtained after integrating the differential equation?
X(y) = y^3 + C
X(y) = 1/(2y^2) + C
X(y) = -1/(2y^2) + C
X(y) = y^2 + C
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the constant C determined in the particular solution?
By setting y = 0
By setting x = 1
By using the initial condition y(0) = 1
By differentiating the general solution
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of the constant C in the particular solution?
1
0
1/2
-1/2
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What operation is performed to isolate the term with y^2 in the equation?
Division
Multiplication
Subtraction
Addition
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final form of y after solving the equation?
y = ±√(2/(1-x))
y = ±√(1/(2x-1))
y = ±√(1/(x-2))
y = ±√(1/(1-2x))
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